TM 5-809-3/NAVFAC DM-2.9/AFM 88-3, Chap. 3
(d) Lateral wind load (w) = 30 lb/ft2. The wind load is positive (inward) on the exterior face of the
wall.
(e) Axial load (P) = 300 lb/ft.
(f) Eccentricity (e) = 1 inch. The axial load is applied on the interior side of the wall center line
causing a condition where the eccentric and lateral load moments are not additive.
(g) f'm = 1350 lb/in2
(h) Fs = 24,000 lb/in2
(i) As shown in figure 6-3, a 12 feet wide by 14 feet high door is located in the wall panel. One
edge of the door is 6 feet 8 inches from the wall corner.
(2) Problem. Design a stiffener at the door jamb that will resist the applied lateral and axial loads.
(3) Solution. Assume that the edge stiffener resists the wind load between the middle of the door and
the middle of the 6*-8" wall panel. Also, assume that the stiffener resists the wall weight and the axial load
to the middle of the door plus the width of the stiffener.
(a) Determine the wind load, WL, on the edge stiffener.
WL = w Lx
Where:
Lw = The tributary width of the load to the jamb, feet.
(b) Determine the moment resulting from the eccentricity of the axial load, Mecc.
Mecc =PLpe
Where:
Lp = The distance from the edge of the stiffener to the center line of the door, feet.
(c) Determine the distance, x, from the bottom of the wall to where the maximum moment in the
edge stiffener occurs.
(d) Determine the maximum moment in the edge stiffener, Mmax, as follows:
6-8
Previous Page
