fa = 38.3 lb/in2 < Fa = 212.0 lb/in2

...O.K.

Combined Load Check: Since the masonry resisting moment controls, only the masonry need be checked in

the combined stress condition. The unity equation will be used. Since wind loadings `are a part of the loading

combination, the allowable axial compressive stress, Fa, may be increased by 33%.

Fa = 1.33(212.0 lb/in2) = 282.0 lb/in2

...O.K.

Direct solution (table B-47): Using the design parameters given above; the 1-#6 bar spaced at 24 inches o.c.

which was determined by the design calculations; is sufficient reinforcement.

(4) *Summary*. 1-#6 bar per cell spaced at 24 inches o.c. is sufficient.

loading. When performing a complete wall design, all appropriate load combinations must be considered.

(1) *Given*:

(2) *Problem*. Find the required spacing of #6 bars using the tables in appendix B and linear

(3) *Solution*. Interpolating for wall height, axial loading, and wind loading.

Smax = 57.1 - (57.1 - 53.3)[(650 - 500)/500] = 56 inches o.c.

(4) *Summary*. The wall will resist the given loading with #6 bars spaced at 56 inches on center.

loading. When performing a complete wall design, all appropriate load combinations must be considered.

(1) *Given*.

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