-Assume that the edge distance for anchors > than 6" = embedment length
Strength based on steel:
Ps = 0.9AbFun
(FEMA 302 Eq. 9.2.4.1-1)
2
Ps = (0.9)(0.6in. )(58 ksi)(1) = 31.3 kips (139 KN)
φ c = φ fc' (2.8A s )n
λ
Strength based on concrete:
(FEMA 302 Eq. 9.2.4.1-2)
P
φ c = (0.65)(1.0) 3000 (2.8)(π)(6) 2 (1) = 11.3 kips (50.3 KN) (governs)
P
Shear strength of bolts:
Vs = 0.75A b Fu n
Strength based on steel:
(FEMA 302 Eq. 9.2.4.2-1)
Vs = (0.75)(0.60)(58)(1) = 26.1 kips (116 KN)
φ c = φ 00A b λ fc' n
Strength based on concrete:
(FEMA 302 Eq. 9.2.4.2-2)
V
8
φ c = (0.65)(800)(0.6)(1.0) 3000 (1) = 17.1 kips (76.1 KN) (governs)
V
Shear force demand = vertical component of brace capacity = 168 kips (753 KN)
Number of bolts required = 168 / 17.1 = 9.8 bolts, use 10 bolts @ 12" (0.31m) on center.
1 inch = 25.4 mm
H3-60
Previous Page
