5
∆ c( 10.ft ,19.67.ft ) ∆ solid = 8.737 10
∆ solid
Solid wall ABCD
in
5
∆ f( 8.ft ,19.67.ft )
∆ bcd
∆ bcd = 5.2219 10
Subtract strip BCD
in
5
∆a
∆ solid
∆ bcd
∆ a = 3.5151 10
in
1
R f( 8.ft ,3.25.ft )
R b = 959.581
Add back in piers B, C and D
Rb
in
1
R d = 959.581
Rd
Rb
in
1
R f( 8.ft ,6.5.ft )
R c = 4146.9681
Rc
in
1
∆ bcd
∆ bcd = 0.0002 in
Rb
Rc
Rd
∆ total
∆a
∆ bcd
∆ total = 0.0002 in
1.kip
kip
KN
R wall = 4999.9934
R wall = 875.6126
R wall
∆ total
in
mm
Shear walls 2A-2D & 2F-2I
5
∆ c( 10.ft ,27.67.ft )
∆ solid
∆ solid = 5.2859310
Solid wall
in
1.kip
kip
KN
R wall = 18918.15
R wall = 3313
R wall
∆ solid
in
mm
Distribute the shear force tributary to the lower sloped roof areas to the shear walls.
Total weight tributary to the lower sloped roof areas = 216.7 kips (964KN)
Weight of each lower sloped roof area = 216.7 / 2 = 108.4 kips (482 KN)
H3-23