dhaunch = 7.00" (177.8mm)

tf = 0.420" (10.7mm)

0.8(1.5(1,557"k ))

= 91.1k (405.2KN)

∴ Ru =

13.91"+ 7.00"- 0.42"

Determine Capacity;

(R v ) W14X34 = 158k (702.8KN)

(calculated

previously)

Check;

Check panel-zone thickness;

t ≥ (d z + w z ) / 90

(EQ. 9-2 AISC Seismic provisions)

dz = 13.91"+7.00"-2(0.42") = 20.1" (510.5mm)

wz = dc-2tf = 13.98"-2(0.455") = 13.1" (332.7mm)

20.1"+ 13.1" d z + w z

∴ t = 0.285" < 0.369" =

=

(7.24mm < 9.37mm)

90

90

Try a 3/8" (9.53mm) thick doubler plate (using ASTM A36);

Provide weld to match shear strength of the required thickness of doubler plate (use E70XX electrode);

Shear capacity of doubler plate = *φ *BM A g = *φ *BM t d b d

F

F

where; FBM = nominal shear capacity of base metal = 0.6Fy

Ag = gross area of the doubler plate

td = thickness of doubler plate

bd = width of doubler plate

Shear capacity of welds = *φ *w (0.707s)b d

F

Where; FW = nominal shear capacity of welds = 0.6FEXX

s = weld leg length

Therefore;

F

F

F

0.9(0.6(36ksi))0.369"

s=

=

= 0.322" (8.18mm)

or

0.707(*φ *W )

F

0.707(31.5ksi)

From AISC J2.2b, the maximum weld size is;

1" 3" 1"

s = td -

=-

= 0.313" (7.95mm)

16 8 16

Try a 1/2" (12.7mm) thick doubler plate with a 3/8" (9.53mm) weld;

For a 1/2" (12.7mm) thick doubler plate;

s = 0.438" (11.13mm)

From AISC table J2.4, the minimum weld size is;

s = 3/16" < 3/8" (4.76mm < 9.53mm)

H4-51

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