30 June 2001
Ap = the cross-sectional area of 1 meter (1 foot) of pavement, square millimeters (square
In determining the percent of steel required in the transverse direction, it is assumed that 6-meter
(20-foot) paving lanes will be used along with the following equation:
The design percent steel in the transverse direction is therefore 0.022. The cross-sectional area of steel
required per 300 millimeters (12 inches) of pavement for the 405-millimeter (16.0-inch) pavement is
The percent steel for other traffic areas would be computed in the same manner.