CEMP-E
TI 809-07
NOVEMBER 1998
b. Problem: Check the design of the wall system described above. Check the allowable
flexural stress and the allowable deflection of the steel studs due to that loading.
c. Solution:
(1) Member loading requirements: Since the steel studs are to be designed to
resist the total lateral (wind) loading, the anchors need to be selected to transfer the
lateral loading from the brick wythe to the steel studs.
(2) Assumptions:
(a) Studs: The minimum stud to be checked is: a 152 mm (6 ") stud;
1.438 mm (0.0566 ") thickness, 41 mm (1-5/8 ") flange width and with a 13 mm
(1/2 ") return. Studs will be spaced on 406 mm (16 ") centers.
(b) Anchors: The brick wythe is attached to the steel studs backup wall
with 4.8 mm (3/16 ") diameter corrosion resisting veneer anchors spaced 406
mm (16 ") on center both vertically and horizontally.
(3) Check stud strength:
(a) Section Properties: From the American Iron and Steel Institute (AISI,
Specification for the Design of Cold-Formed Steel Structural Members, Part V,
"Charts and Tables".
Thickness of sheet (t) = 1.438 mm (0.0566 "),
Depth of section (D ) = 152 mm (6.00 "),
stud
Width of flange (B) = 41 mm (1.625 "),
Return of flange (C) = 15 mm (0.60 "),
3
3
Section Modulus (S ) = 17,649 mm (1.077 in ),
x
4
4
Moment of inertia (I ) = 1,318,205 mm (3.167 in ),
x
Area of section (A
) = 15.6 mm (0.616 ").
stud
(b) Steel Properties:
Modulus of elasticity (E ) = 200,000 MPa (29,000,000 psi),
s
Yield strength (F ) = 228 MPa (33,000 psi).
y
(c) Design check: The uniform wind load normal to the wall, w, in N/m
(lbs/ft) of wall, is:
406mm
(Eq 4-13)
544N / mm...(37.3plf )
w
(1.34KPa)
C4
Where:
C4 = constant = 1 - metric, (12 English)
The moment in steel stud due to wind load, M , is:
s
wL 2
544 N / m ..( 3 .66 m )2
(Eq 4-14)
Ms
911 .N
m...( 672 ft
lbs )
8
8
4-8
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