Mtot = 40 + 192 = 232 in-kips

the pilaster is added to P):

Where:

Fa = [0.18f'm + 0.65 pgFSC]R

=[0.18(1350) + 0.65(0.0246)(24,000)]R = 627(R) psi

Where:

So;

Fa = 627 psi (0.973) = 610 psi

fa = 114 psi < Fa = 610 psi

...O.K.

Where:

d = 15.62 in - 3.5 in = 12.12 in; use d = 12 in.

AsT = The area of the reinforcement that is in tension, which is 3-#9 bars.

AsT = 3(1.00 in2) = 3.00 in2

p = AsT/bd = 3.00 in2/(15.62 in 12 in) = 0.016

np = 21.5(0.016) = 0.344

...O.K.

eccentricity (without the 1/3 increase in allowable stresses for wind loading). The flexural compressive stress,

fb, is determined as follows (Note. Assume a cracked section):

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