Shear wall line 8 receives shear from both sacristy areas. Therefore, it is assumed that of the rigidity of

the entire wall (=1/2 * 43743 = 21872 k/in) will be used in determining the distribution of forces to

vertical resisting elements tributary to each sacristy area.

For each sacristy;

Rwall 7 = 5000 kips / in (876 KN/mm)

Rwall 8 = 21872 kips /in (7660 KN/mm)

Shear force tributary to each sacristy = 5.3 kips (23.6 KN)

R element

Velement = V

R7 = 5000 kips / in R8 = 21872 kips / in

∑R

V7A-7C = 5.3(5000) / (21872+5000) = 0.99 kips (4.40 KN)

V8= 5.3(21872)/(21872+5000) = 4.31 kips (19.2 KN)

Due to symmetry, V7G-7I = V7A-7C = 0.99 kips (4.40 KN)

Total shear to wall line 8 (for forces trib. to sacristies) = 2(4.31 k) = 8.62 kips (38.3 KN)

Longitudinal Direction

Rigidity of shear wall lines A & I: It is assumed that only the end portion ot the walls (between grid lines

7 and 8) resist shear forces tributary to the sacristy areas (this is a very conservative assumption since the

walls run the full length of the building).

1 foot = 0.305m

H3-29

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